Question: 4. We can define a special group product, x, between two cyclic groups, Zn and Zm, on the set Zn X Zm, where the group

4. We can define a special group product, x,
4. We can define a special group product, x, between two cyclic groups, Zn and Zm, on the set Zn X Zm, where the group operation, , is given by (i, x) O (j,y) = (it (-1)"j, xty), i,jeZn, x,y EZm, where arithmetic in the first coordinate is (mod n) and (mod m) in the second. So, for example, in Z1 x Z2: (2, 1) @ (3, 0) = (2+ (-1)' 3, 1+ 0) = (2 - 3, 1) = (-1, 1) = (3, 1) (2, 1) @ (3, 1) = (2+ (-1)1+13, 1 + 0) = (2+ 3, 1 + 1) = (1,0) Recall that Dn = {e, r, .. ., r-1, ra, ..., r"-la}, where r| = n, la) = 2, and ria = ar-. Show that Zn X Z2 ~ Dn

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