${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{4x^2+x+12}{x^3+4x}dx$

A$)3ln|x|-\frac{1}{2}ln|x^2+4|-ta{n}^{-1}x+C$

B$)ln|x|+\frac{1}{2}ln|x^2+4|+ta{n}^{-1}(\frac{x}{2})+C$

C$)3ln|x|+\frac{1}{2}ln|x^2+4|+si{n}^{-1}(\frac{x}{2})+C$

D$)3ln|x|+\frac{1}{2}ln|x^2+4|+\frac{1}{2}ta{n}^{-1}(\frac{x}{2})+C$