${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}4x\sqrt[\phantom{2}]{x-1}dx=$

$($A$)\frac{8}{5}(\sqrt[\phantom{2}]{x-1}{)}^5+\frac{8}{3}(\sqrt[\phantom{2}]{x-1}{)}^3+C$

$($B$)\frac{8}{5}(\sqrt[\phantom{2}]{x-1}{)}^5+\frac{2}{3}(\sqrt[\phantom{2}]{x-1}{)}^3+C$

$($C$)3x^2(x-1{)}^{\frac{1}{2}}+C$

$($D$)2x^2+\frac{3}{2}(x-1{)}^{\frac{3}{2}}+C$

$($E$)4(x-1{)}^{\frac{3}{2}}+4(x-1{)}^{\frac{1}{2}}+C$