Question: 4. x2 + 3y2 = 9 5. 25x2 + 16y2 = 400 6. 9x2 + 49y2 = 441B. C. Find an equation for the ellipse

axis: 5 units; foci on y-axis (0, +12 ) 4. Foci: F(0,

+3); length of minor axis: 4 units 5. Distance between foci: 8

4. x2 + 3y2 = 9 5. 25x2 + 16y2 = 400 6. 9x2 + 49y2 = 441B. C. Find an equation for the ellipse with the given conditions. 1. Foci: F(+6, 0); vertices: (+7, 0) 2. Foci: F(+3, 0); vertices: (+4, 0) 3. Length of minor axis: 5 units; foci on y-axis (0, +12 ) 4. Foci: F(0, +3); length of minor axis: 4 units 5. Distance between foci: 8 units; endpoints of major axis: (+10, 0)B. Find a) the vertices, b) the foci, and c) the lengths of the major and minor axes of each given equation of an ellipse, then graph. 1 . yz 9 + 25 = 1 2. X2 yz 49 + 25 = 1 3. 4x2 + y2 = 1A. Write each equation of the ellipse in standard form. 1. 16x2 + 9y2 = 144 2. 81x2 + 16y2 - 1 296 = 0 3. 4x2 + 25y2 + 8x = 96 4. x2 + 4y2 - 32y + 28=0 5. 49x2 + 4y2 - 196x - 40y + 100 =0

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