Question: 40. Two identical strings (same mass and length), each fixed at both ends, are arranged near each other. If string A starts oscillating in

40. Two identical strings (same mass and length), each fixed at both

40. Two identical strings (same mass and length), each fixed at both ends, are arranged near each other. If string A starts oscillating in its fundamental mode, it is observed that string B will begin vibrating in its third ormal mode (-3). What is the ratio of the tension in string B to that in string A? (Ans: 1/9) antinodes velocity L Aca Bee (= 1 + 1) = ) Latt A X = 1 TA 2 (11) u B Y = 3/ = STA A |= 2(2) X XPE JTB JTB Could tell me why my O steps f = n 22 length is incorrect? 0

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