Question: 40. Two identical strings (same mass and length), each fixed at both ends, are arranged near each other. If string A starts oscillating in
40. Two identical strings (same mass and length), each fixed at both ends, are arranged near each other. If string A starts oscillating in its fundamental mode, it is observed that string B will begin vibrating in its third ormal mode (-3). What is the ratio of the tension in string B to that in string A? (Ans: 1/9) antinodes velocity L Aca Bee (= 1 + 1) = ) Latt A X = 1 TA 2 (11) u B Y = 3/ = STA A |= 2(2) X XPE JTB JTB Could tell me why my O steps f = n 22 length is incorrect? 0
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To determine the ratio of the tension in string B to that in string A we can analyze the given scenario and the equations provided Lets go through the ... View full answer
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