$5\mathrm{.}14$ Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to

determine its unit weight. The following data are obtained:

Volume of bucket $=\frac{1}{2}f{t}^3$

Weight of empty bucket $=20\mathrm{.}3lb$

Weight of bucket filled with dry rodded coarse aggregate:

Trial $1=76\mathrm{.}6lb$

Trial $2=75\mathrm{.}1lb$