$5$

$1$ point

A vertical, circular tube has an inside diameter of $1$ mm $.$ A liquid of $=0\mathrm{.}098\frac{N}{m}$ rises into the tube to some height $h.$ Assuming the rise is only due to surface tension and

assuming a contact angle of $0,$ if the liquid density is $12,746k\frac{g}{m^3}$ and the gravity is $9\mathrm{.}81\frac{m}{s^2},$ what is h in cm $?$

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