$5/20$

Write a program that first gets a list of integers from input. The input begins with an integer indicating the number of integers that follow. Then, get the last value from the input, which indicates a threshold. Output all integers less than or equal to that last threshold value.

Ex: If the input is:

$5506014020075100$

the output is:

$50,60,75,$

The $5$ indicates that there are five integers in the list, namely $50,60,140,200,$ and $75.$ The $100$ indicates that the program should output all integers less than or equal to $100,$ so the program outputs $50,60,$ and $75.$

For coding simplicity, follow every output value by a comma, including the last one.

Such functionality is common on sites like Amazon, where a user can filter results.

#include

#include

using namespace std;

int main$()\{$

vector userVals;

int numVals;

int currVal;

int threshold;

cin $>>$ numVals;

for $($int i $=0$; i $<$ numVals; $++$i$)\{$

cin $>>$ currVal;

userVals.push$\_$back$($currVal$)$;

$\}$

cin $>>$ threshold;

for $($int i $=0$; i $<$ numVals; $++$i$)\{$

if $($userVals$.$at$($i$)<=$ threshold$)\{$

cout $<<$ userVals.at$($i$)<<","$;

$\}$

$\}$

cout $<<$ endl;

return $0$;

$\}$#include

#include

using namespace std;

int main$()\{$

vector userVals;

int numVals;

int currVal;

int threshold;

cin $>>$ numVals;

for $($int i $=0$; i $<$ numVals; $++$i$)\{$

cin $>>$ currVal;

userVals.push$\_$back$($currVal$)$;

$\}$

cin $>>$ threshold;

for $($int i $=0$; i $<$ numVals; $++$i$)\{$

if $($userVals$.$at$($i$)<=$ threshold$)\{$

cout $<<$ userVals.at$($i$)<<","$;

$\}$

$\}$

cout $<<$ endl;

return $0$;

$\}$