Question: 5 2 8 0 4 0 . 3 4 8 9 5 2 8 . q 3 z q y 7 Jump to level 1

528040.3489528.q3zqy7
Jump to level 1
String dataString is read from input. Append each unique character found in dataString to uniqueCharacters in the order that the character first appears.
Ex: If the input is Pennsylvania, then the output is:
Unique characters found: P,e,n,s,y,l,v,a, i
Note: dataString.indexOf(dataString.charAt(i))== i returns true if dataString.charAt(i) occurs the first time at index i of dataString.
import java.util.Scanner;
public class ExtractUniqueCharacters {
public static void main(String[] args){
Scanner scnr = new Scanner(
System.in);
String datastring;
int i;
String uniqueCharacters =";
dataString = scnr. nextLine ();
I* Your code goes here */
System.out.print("Unique characters found: ");
for (i=0; i uniqueCharacters.length ();++i){
System.out.print (uniqueCharacters.charAt(i));
if (i != uniqueCharacters.length()-1){
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 528040.3489528.q3zqy7 Jump to level 1 String dataString is read from input.

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