Question: ( 5 . 2 9 ) In a p + n diode reverse biased at 5 V , the generated capacitance is 2 0 pF

(5.29)
In a p+n diode reverse biased at 5 V , the generated capacitance is 20 pF . If the doping of the p side is doubled and the bias is change to 20 V , what will be the change in capacitance? If now the bias is changed to 100 V , then what will be the change?
( 5 . 2 9 ) In a p + n diode reverse biased at 5

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