Question: 5] (20 pts. total) Two algorithms have the following count functions: C1(n)=42nn and C2(n)=2n2. (a) Obviously, the second algorithm has the largest order of growth,
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5] (20 pts. total) Two algorithms have the following count functions: C1(n)=42nn and C2(n)=2n2. (a) Obviously, the second algorithm has the largest order of growth, but someone says: 'For n=1,C1 gives 4 basic operations, whereas C2 gives only 2 , therefore the first algorithm must have a larger nr. of basic operations.' How do you reply? Answer ( 2 pts.): (b) (17 pts.) Write a C program to verify the behavior you described above, and to find the intersection point for the functions. The program should use a loop to display on each line the values of n,C1(n), and (You will not need to go up to 1000, this is just an example of how the output should be formatted.) Attach screenshots of your source code and output (c) Use the output from the program to answer the question: What is the first integer n for which C2(n) is larger than C1(n) ? Answer (1 pt.)
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