$[5]$ A particle moves along the curve $(y-1{)}^3=\frac{27*x^2}{8}$ in the first quadrant of the $x-y$ plane starting at $(1,\frac{5}{2}).$

The $x-$component of its velocity is given by $v_x(t)=\frac{27}{32}t$ for $t>0.$

What is the y$-$component of the particle's velocity as a function of time? $($Enter the exact answer with integers or rational numbers only.$)$

$v_y(t)=$

$271$

Your last answer was interpreted as follows:

$\frac{27}{32}*t$

The variables found in your answer were: $t$

Incorrect answer.