5. Consider the function f(x) = 23 +322 on the closed interval -3x2. (a) Find where the global maximum and global minimum occur. f(x)=(x3 + 3x 2 2-1 f'(x) = 3x+ 6x- (3)=3(-3)+6(3) F'(3) = 27-18=9 how do you find possi ble locations of extreme from here? You should test endpoint with flx), not F(2) = 3(2)+6 (2) F(2) = 12 +12=24 f(0) = 0 f(x) = x+3x2 (3)9+3(3) q (b) What are the global maximum and global minimum values from part (a)? Global maximum is 247