$[-/5$ Points$]$

If $g(s)=6\sqrt[\phantom{2}]{s}\frac{3}{s}\frac{4}{\sqrt[\phantom{2}]{s}}85,$ find $g^{\text{'}}(s).$

$\frac{3}{\sqrt[\phantom{2}]{5}}-\frac{3}{5^2}-\frac{2}{5^{\frac{3}{2}}}$

$\frac{3}{\sqrt[\phantom{2}]{s}}-\frac{3}{s^2}\frac{2}{s^{\frac{3}{2}}}$

$\frac{6}{\sqrt[\phantom{2}]{5}}-\frac{3}{5^2}\frac{2}{5^{\frac{3}{2}}}85$

$\frac{6}{\sqrt[\phantom{2}]{s}}\frac{3}{s^2}-\frac{2}{s^{\frac{3}{2}}}$

$\frac{3}{\sqrt[\phantom{2}]{5}}\frac{3}{5^2}\frac{4}{5^{\frac{3}{2}}}$

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