$(5$ pts $)10.$ A bullet with mass $0\mathrm{.}040$ kg is traveling horizontally with a speed $v_0$ when it strikes a wooden block that has mass $2\mathrm{.}96$ kg $.$ The bullet remains embed in the block and the block with the bullet in it $($total mass $2\mathrm{.}00$ kg $)$ slides $2\mathrm{.}00$ m on a horizontal surface before it comes to rest. If the coefficient of kinetic friction between the block and the surface is ${}_k=0\mathrm{.}40,$ what was the speed of the bullet just before it struck the block?

$($a$)100\frac{m}{s}$

$($b$)150\frac{m}{s}$

$($c$)200\frac{m}{s}$

$($d$)250\frac{m}{s}$

Vo

$($c$)300\frac{m}{s}$

$($t$)$ none of these answers

Please help me understand how it is $300$ m$/$s$.$ I will like.