Question: 5.8 Consider a class DateToDay that contains a method char* convert (int, int, int). It converts the date into day, and the precondition is that

 5.8 Consider a class DateToDay that contains a method char* convert

(int, int, int). It converts the date into day, and the precondition

is that all three integers of the date are two-digit integers, representing

the month, day of the month, and a year (see the enclosed

5.8 Consider a class DateToDay that contains a method char* convert (int, int, int). It converts the date into day, and the precondition is that all three integers of the date are two-digit integers, representing the month, day of the month, and a year (see the enclosed code). Change the precondition of convert in such a way that the year is a four-digit integer, like 2010. Take into account the corresponding quirks of the Gregorian calendar. class DateToDay public: char* convert (int dd, int mm, int yy) if (!( dd >0&& dd 0&& mm

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