Question: 6 . 2 . 5 Deformation Intermediate Given the information in the graphic above, what is the total deformation of the aluminum ( (

6.2.5 Deformation
Intermediate
Given the information in the graphic above, what is the total deformation of the aluminum (\( E_{A 1}=73\)[GPa]) bar system due to loading? The cross-sectional area of member \( A B \) is taken as \(25\left[\mathrm{~mm}^{2}\right.\)], and that of member \( B C \) is taken as \(75\left[\mathrm{~mm}\mathrm{~m}^{2}\right.\)]. Units taken as [m]; do not report units with your answer. The use of significant digits is not required. If the bar is extending by this amount report a positive value. If it reduced by this amount report a negative value.
Figure References: All figures created by wathor(s) using Adobe Illustrator with permission.
Type your numaric answar and submit.
Hint
Recall deformation due to applied loading is the linear strain times the initial length. The linear strain is the normal stress in the member divided by the Modulus of Elasticity. Stress is the internal reactionary forces divided by the cross-sectional area.
6 . 2 . 5 Deformation Intermediate Given the

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