$6\mathrm{.}3.$ In example #$3$ of the lecture notes we rotated the region bounded by the curve $y=x-x^2$ and the $x-$axis about the vertical line $x=2$ using vertical shells. The volume integral was $,V=2{\displaystyle \underset{0}{\overset{1}{}}}(2-x)(x-x^2)dx.$ Do the same but now use a horizontal annulus $($i$.$e$.,$ the "disk method"$).$ Set up the integral but don't evaluate it$.$

HELP: $y=x-x^2$ is reversible using the quadratic formula applied to $1x^2-1x+y=0$ with $a=1,b=-1,c=y$