Question: ( 6 ) ' = ( 5 x 2 + 3 x + 7 ) ' = ( 5 x 6 + 4 x 3

(6)'=
(5x2+3x+7)'=
(5x6+4x3-7x-9)'=
(sin(2x))'=
(cos(3x))'=
( 6 ) ' = ( 5 x 2 + 3 x + 7 ) ' = ( 5 x 6 + 4 x 3

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