6 Firefox File Edit View History Bookmarks Tools Window Help @ 7,. LE E 4;? 84%9} Mon 5:55 PM Q 0 25 r ' O O 6 WtMidtermExam-MAT135,secu X + v ' 6 A C 0 E] https://www'webassign.net/web/Student/AssignmentResponses/submit?dep=3'l640076&tags=autosave#question1923673_'l6 IE i} i] E Tutorial Exercise Use synthetic division and the Factor Theorem to determine whether the given binomial is a factor of P00. P(x) = x5 + 5x4 27x3 51x2 + 60X, x 4 Part1 of5 Begin with performing synthetic division with c = 4 v f) 4 and examine the remainder. 4 1 5 27 51 60 0 4 36 36 '/ ,236 60 0 V /)0 1 9., /9 9" /)9 15 o.' ,m 0 yo Part20f5 Based on the synthetic division from the step above, the remainder is 0 v /) 0 . Therefore, P(4) = 0 v / 0 Part3 of5 Now recall the Factor Theorem. A polynomial P(x) has a factor (x c) if and only if P(c) 0. That is, (x - c) is a factor of P(x) if and only if c s q ,2 is a zero of P. ll \\ n Part4 of5 Because P(4) = o, x 4 a factor of P(x) = x5 + 5x4 27x3 51x2 + 60X. Submit EL (you cannot come back) Firefox File Edit View History Bookmarks Tools Window Help BE 85% [4 Mon 5:56 PM A Midterm Exam - MAT 135, section X + C O & https://www.webassign.net/web/Student/Assignment-Responses/submit?dep=31640076&tags=autosave#question1923673_16 E Tutorial Exercise Use synthetic division and the Factor Theorem to determine whether the given binomial is a factor of P(x). P(x) = x5 + 5x4 - 27x3 - 51x2 + 60x, x - 4 Part 1 of 5 Begin with performing synthetic division with c = 4 4 and examine the remainder. 1 5 -27 -51 60 C 4 36 36 36 -60 O V 0 1 9 0 $ 9 9 9 -15 O V Part 2 of 5 Based on the synthetic division from the step above, the remainder is o| ~ o . Therefore, P(4) = 0 ~ o Part 3 of 5 Now recall the Factor Theorem. A polynomial P(x) has a factor (x - c) if and only if P(c) = = 0. That is, (x - c) is a factor of P(x) if and only if c is is a zero of P. Part 4 of 5 Because P(4) = 0, x - 4 v ---Select--- actor of P(x) = x5 + 5x4 - 27x3 - 51x2 + 60x. is Submit Skip (you cannot is not 120 APR 6 ... 24 A