Question: 6 . How many bits are required for addressing ( i . e . what is the size, in bits, of a memory address )

6. How many bits are required for addressing (i.e. what is the size, in bits, of a memory address)?
a.32 bits
b.30 bits
c.28 bits
d.31 bits
e.16 bits
17. How will the bits in the instruction be distributed between opcode and operands? Answers are
listed as bits for opcode / bits for operands
a.4 bits /20 bits
b.4 bits /28 bits
c.5 bits /19 bits
d.5 bits /27 bits
e.6 bits /26 bits
18. How many bits can be used to represent an immediate value as an operand?
a.32 bits
b.20 bits
c.28 bits
d.1 bit
e.6 bits
19. How far (in memory locations) can the label be from an instruction that references the label, using
the addressing mode?
a.+/-256 K
b.+/-128 K
c.+/-16 k
d.+/-32 K
e.+/-4 K
5

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