6. Oxalic acid reacts with the chromate ion in acidic solution as follows:  H2C2O4(aq) + 2 CrO42- (aq) + 10 H+  6 CO(g) + 2 Cr3+(aq) + 8 H2O(l)

2.5683g of K2CrO4 was weighed out, dissolved and diluted to 500mL in a volumetric flask. Calculate the molarity of the oxalic acid if a 25.00 mL aliquot of this acid solution consumed 28.54 mL of the chromate solution.

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H2C2O4aq 2 CrO42 aq 10 H 6 COg 2 Cr3aq 8 H2Ol molec... View the full answer