Question: ( 6 points ) Consider the following function f ( x ) = 1 + x 2 3 1 x - 1 = 3 e

(6 points) Consider the following function
f(x)=1+x231x-1=3e1+x2=>3ex2
Find the Taylor polynomial T2(x)of degree 2 near x=0off(x).
f(a)=32(1+x)12=xn,x2=f(0)+f(0)'1!x-a+f''(0)2!(x-a)2+f'''(c)3!
f'(0)=1e2a=(32)(12)(1+x)=Z(1+x)!T2=f(a)+f(a)'1!x+f(a)''2!x2
f''(x)=12e=4(1+x2)!
T2=3ex2+1e2xx+12!x2
T2=32(1+x)12+2(1+x)!1!x+4(1+x2)!2!x2
( 6 points ) Consider the following function f (

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