6) Solve the following inequality algebraically. Include an interval chart in your solution. 5x+4 5x-7 x-11 x+13 {5}52 +4 5x - 7 2-11 x + 13 To solve this for x LHS defined only if denominator x -11 0 => x#11 0 and to the RHS deferied only if denominator at 13+ 0 =3 27-13 -2) so, we consider both denominators x-ll to and x+13 to x: #11 and X # -13 526 + 4 :2 . 5x-7 X -11 x + 13 5 x2 + 4 ) ( x + 13 ) 2 (5 x-7)( x-11) 5 x2 + 6 9 x + 52 25 131 Also x - 110 : 52 4 11 $ 2 xe (-0, -13) 0 ( 25 , 11)D DMM YY Y Y 2 x/ 6 0 - 13 ) O O- -O -13 0 25 11 Do 131