Question: 6 . The 4 5 - degree prism shown is to be used to deflect light by 9 0 degrees, so the facet should provide

6. The 45-degree prism shown is to be used to deflect light by 90 degrees, so the facet should provide total internal reflection.
a) For normal incidence light, what is the minimum value of the index of refraction \( n \) such that the prism functions as intended?
b) What is the fraction of transmitted power at normal incidence (the ratio of the intensity in air propagating down after deflection to the intensity incoming from the left) as a function of the index \( n \)? What is the value of the transmitted fraction for the specific value of \( n \) found in part (a)? You may assume the dielectric material has \(\mu=\mu_{0}\).
c) If it is required that any rays within an acceptance angle of \(\pm 15^{\circ}(\pm \pi /12)\)- as measured inside the prism - should also be deflected by total internal reflection at the 45-degree facet, what is the minimum value of index \( n \) needed? What is the acceptance angle in air \(\theta_{a}\) that corresponds to \(15^{\circ}\) inside the prism? You may use \(\sin (\pi /12)=0.25\).
6 . The 4 5 - degree prism shown is to be used to

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