Question: 6 The linear transformation $left(begin{array}{1}x^{prime} y^{prime} end{array} ight)=left(begin{array}{11}-3 & 1 1 -1 & 4end{array} ight)left(begin{array}{1}x yend{array} ight)+left(begin{array}{c}-1 2end{array} ight)$ maps the points $(x, y)$

 6 The linear transformation $\left(\begin{array}{1}x^{\prime} \ y^{\prime} \end{array} ight)=\left(\begin{array}{11}-3 & 1

6 The linear transformation $\left(\begin{array}{1}x^{\prime} \ y^{\prime} \end{array} ight)=\left(\begin{array}{11}-3 & 1 1 -1 & 4\end{array} ight)\left(\begin{array}{1}x y\end{array} ight)+\left(\begin{array}{c}-1 \\2\end{array} ight)$ maps the points $(x, y)$ to $\left(x^{\prime), y^{\prime} ight)$. Find a the coordinates of the image of $(-3,5)$ b the coordinates of the point who image is $(-7,0$ c the coordinates of the image of $(a, 2 a) $ where $a \in \mathbb{R}$. CS. JG. 102

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