Question: 600mW = _________dBW a. 60 dBW b. 0.6 dBW c. -2.2 dBW d. 27.8 dBW -85 dBm = _________mW a. 3.16E-9 mW b. 3.16E-12 mW

600mW = _________dBW

a. 60 dBW

b. 0.6 dBW

c. -2.2 dBW

d. 27.8 dBW

-85 dBm = _________mW

a. 3.16E-9 mW

b. 3.16E-12 mW

c. -115 mW

d. -55 mW

-30dBW = _________dBm

a. -30dBm

b. 0dBm

c. +30dBm

d. -60dBm

Which multiplexing technique can be used with analog basebands?

a. FDMA

b. TDMA

c. CDMA

d. Both FDMA and TDMA

Select the correct statement(s) regarding error detection.

a. A codeword represents information bits

b. A dataword is comprised of both the codes work plus check bits

c. The dataword goes through a specific error detection algorithm in order to compute error detection bits that are then appended to the dataword for transmission

d. The codeword goes through a specific error detection algorithm in order to compute error detection bits that are then appended to the codeword for transmission

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