Signals g1 (1) = 10* n(10*1) and g2(1) = 5(1) are applied at the inputs of...

 

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Signals g1 (1) = 10* n(10*1) and g2(1) = 5(1) are applied at the inputs of ideal low-pass filters H1f) = nG/20,000) and H2(f) = nf/10,000) (Fig. P6.1-5). The outputs yy (1) and y2(0) of these filters are multiplied to obtain the signal y(1) = y (t)y2(1). Find the Nyquist rate of yi (1). y2(1), and y(r). Use the convolution property and the width property of convolution to determine the bandwidth of yy (1)y2(1). Figure P.6.1-5 ,(1) (1) Signals g1 (1) = 10* n(10*1) and g2(1) = 5(1) are applied at the inputs of ideal low-pass filters H1f) = nG/20,000) and H2(f) = nf/10,000) (Fig. P6.1-5). The outputs yy (1) and y2(0) of these filters are multiplied to obtain the signal y(1) = y (t)y2(1). Find the Nyquist rate of yi (1). y2(1), and y(r). Use the convolution property and the width property of convolution to determine the bandwidth of yy (1)y2(1). Figure P.6.1-5 ,(1) (1)

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Given 10 80 92 t 1 9 10 cat H f T F20600 Hz 1 TC 10000 We know that 77 J t Sins ... View the full answer