6-29. In Chapter 4, we learned that if y, and y, are solutions of the Schrdinger equation that have the same energy E, thenc, +c, V, is also a solution. Let y, = 210 and 2 = 4211 (see Table 6.5). What is the energy corresponding to y = c, , +cV where c + ez = 1? What does this result tell you about the uniqueness of the three p orbitals, py, py, and p? =