6.(8 points) A stone thrown vertically upward from the edge of a bridge that is 48 feet above the ground with an initial velocity (i.e. velocity at time t =0) of 32 f t/s. The height above the ground of the stone thrown from the bridge after t seconds is f(t)=16t 2+32t +48.(a) When does this stone reach its highest point and what is this maximum height? (b) When does this stone strike the ground and what is its velocity at the time of impact? (c) Suppose a second stone is thrown vertically upward from the ground. The height above the ground of this second stone after t seconds is given by g(t)=16t 2+ v0t where v0 is the initial velocity. Find the value v0 such that both stone reach the same highest point