$7\mathrm{.}10($Sales Commissions$)$ Use a one$-$dimensional array to solve the following problem: A company pays its salespeople on a commission basis. The salespeople receive $$200$ per week plus $9\%$ of their gross sales for that week. For example, a salesperson who grosses $$5,000$ in sales in a week receives $$200$ plus $9\%$ of $$5,000,$ or a total of $$650.$ Write an application $($using an array of counters$)$ that determines how many of the salespeople earned salaries in each of the following ranges $($assume that each salesperson$$s salary is truncated to an integer amount$)$:

$1.$ $$200299$

$2.$ $$300399$

$3.$ $$400499$

$4.$ $$500599$

$5.$ $$600699$

$6.$ $$700799$

$7.$ $$800899$

$8.$ $$900999$

$9.$ $$1,000$ and over

Summarize the results in tabular format.

this is what i have so far.

import java.util.Scanner;

public class SalesCommission $\{$

public static void main$($String$[]$ args$)\{$

int$[]$ counters$=$new int$[9]$;

Scanner input $=$ new Scanner$($System$.$in$)$;

while $($true$)\{$

System.out.print$("$Please enter gross sales of the week $($ S to stop$)$: $")$;

double sales $=$ input.nextDouble$()$;

if$($sales$==$S$)$

break;

double total $=200+(9/100\mathrm{.}0*$ sales $)$;

System.out.println$("$You will receive $"+$total$+"$ this week."$)$;

int index $=($int$)$total$/100$;

if$($index$>10)$

index$=10$;

counters$[$index$-2]++$;

$\}$

System.out.println$("$Counters are: $")$;

for$($int i$=0$;i$<8$;i$++)$

$\{$

System.out.printf$("$$$[\%$d$-\%$d$]==>\%$d

$",200+$i$*100,299+$i$*100,$ counters$[$i$])$;

$\}$

System.out.println$("$$$1000$ and over $==>"+$ counters$[8])$;

$\}$