#$7,$ #$9,$ #$13$ Use Part $1$ of the Fundamental Theorem of Calculus to find the derivative of the function.

$7.g(x)={\displaystyle \underset{0}{\overset{x}{}}}\sqrt[\phantom{2}]{t+t^3}dt$

$8.g(x)={\displaystyle \underset{1}{\overset{x}{}}}ln(1+t^2)dt$

$9.g(s)={\displaystyle \underset{5}{\overset{s}{}}}(t-t^2{)}^{8}dt$

$10.h(u)={\displaystyle \underset{0}{\overset{u}{}}}\frac{\sqrt[\phantom{2}]{t}}{t+1}dt$

$11.F(x)={\displaystyle \underset{x}{\overset{0}{}}}\sqrt[\phantom{2}]{1+sect}dt$

Hint: $[$:${\displaystyle \underset{x}{\overset{0}{}}}\sqrt[\phantom{2}]{1+sect}dt=-{\displaystyle \underset{0}{\overset{x}{}}}\sqrt[\phantom{2}]{1+sect}dt$