7. A 1.20 kg piece of granite [c, = 0.790 J/(g C)] at 60.0C must...

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7. A 1.20 kg piece of granite [c, = 0.790 J/(g · °C)] at 60.0°C must be cooled to 24.0°C by submersion in water. How much water [c, = 4.18 J/(g °C)] initially at 18°C would be required? 0.302 kg b. 0.907 kg c. 1.36 kg %3D a. d. 1.72 kg e. 8.16 kg 7. A 1.20 kg piece of granite [c, = 0.790 J/(g · °C)] at 60.0°C must be cooled to 24.0°C by submersion in water. How much water [c, = 4.18 J/(g °C)] initially at 18°C would be required? 0.302 kg b. 0.907 kg c. 1.36 kg %3D a. d. 1.72 kg e. 8.16 kg

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Solutions We have the equation of the amount of heat required Q m c T Where m The mass of the ... View the full answer