(7%) Problem 12: Two blocks are connected by a massless strand that passes through the center of a rotating turntable, as shown in the diagram. The blocks have masses M1 = 1.9 kg and M2 = 2.1 kg. Block 1 rests a distance r = 0.48 In from the center of the turntable. The coefcient of static friction between block and turntable is ,u5 = 0.58. Block 2 hangs vertically below. Tran , Theresa - ttran55@mail.sfsu.edu lUtllccxpcrttaxom @theexpertta.com tracking id: 6C657EA041B9BD32189. In accordance with Expert TA's Terms of Service. copying this information to any solutions sharing website is strictly forbidden. Doing so may result in termination of your Expert TA Account. D A Find the speed of circular motion at which block 1 just begins to slip outward along the surface of the turntable. Enter your answer in meters per second. Grade Summary Deductions 0% Potential 100% ( = 4 5 6 Submissions .. Attempts remammg + E (E per attempt) - 0 - detailed View oDegrees " Radians Submit _- I give up! Hints: i fora 0% deduction. Hints remaining: 2 Feedback: 1% deduction per feedback. -What forces are acting on Block 1? -Block 1 has the tension and the force due to friction acting on it, which is making it stick to the turntable and move with it. -What direction must the force of static friction be pointing if the block is just about to move outward? -Draw the free body diagram for both blocks. Write second Newton's law for the rst block. -What is direction of force of friction acting on the rst block if it just about to move outward