7. Take the first smaller subnet from problem #6, and subnet it further so that you have four subnets of 8 IP addresses each. Find the following: the new subnet mask, how many new subnets you have, and what the network address is for each.

subnets from problem #6

subnet 1: ---------- network address: 192.168.0.0 available ip addresses: 30 broadcast address: 192.168.0.31

subnet 2: ---------- network address: 192.168.0.32 available ip addresses: 30 broadcast address: 192.168.0.63

subnet 3: ---------- network address: 192.168.0.64 available ip addresses: 30 broadcast address: 192.168.0.95

subnet 4: ---------- network address: 192.168.0.96 available ip addresses: 30 broadcast address: 192.168.0.127

subnet 5: ---------- network address: 192.168.0.128 available ip addresses: 30 broadcast address: 192.168.0.159

subnet 6: ---------- network address: 192.168.0.160 available ip addresses: 30 broadcast address: 192.168.0.191

subnet 7: ---------- network address: 192.168.0.192 available ip addresses: 30 broadcast address: 192.168.0.223

subnet 8: ---------- network address: 192.168.0.224 available ip addresses: 30 broadcast address: 192.168.0.255