Question: 7 Time left 0:55:38 estion 16 Alternative X has a first cost of $20,000, an operating cost of $9,000 per year, and a $5,000 salvage

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7 Time left 0:55:38 estion 16 Alternative X has a first cost

Time left 0:55:38 estion 16 Alternative X has a first cost of $20,000, an operating cost of $9,000 per year, and a $5,000 salvage yet wered value after 2 years. Alternative Y will cost $35,000 with an operating cost of $4,000 per year and a salvage value of $7,000 after 4 years. At a MARR of 12% per year, when comparing the ked out of alternatives, the equation of PWx is written as: lag question O a. PWX = -20,000 + 9000(P/A,12%,4) + 5000(P/F,12%,4)-15000(P/F,12%,2) b. PWX = -20,000 - 9000(P/A,12%,4) + 5000(P/F,12%,2)-15000(P/F,12%,2) O c. None of these answers O d. PWX = -20,000 - 9000(P/A,12%,4) + 5000(P/F,12%,4)-15000(P/F,12%,4) tion 17 The present worth of a $500 cash flows that starts 3 years from now and continues till year 10, at et an interest rate of 8% per year is calculated using the equation : ered P- 500(P/A, 8%,9) (P/F, 8%,2) ed out of Select one: g question True O False

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