7. Which of the following is not a colligative property? a. osmotic pressure b. c. 8....
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7. Which of the following is not a colligative property? a. osmotic pressure b. c. 8. Sucrose is a nonvolatile, nonionizing solute in water. Determine the vapor pressure lowering, at 27°C, of a solution of water at 27°C is 26.7 torr. Assume the solution is ideal. 0.585 torr 0.058 torr 0.572 torr 5.62 torr d. b. c. d. a. b. C. d. b. C. d. c. a. b. e. 0.548 torr 9. If 4.27 grams of sucrose, C₁2H₂2011, are dissolved in 15.2 grams of water, what will be the boiling point of the resulting solution? Ks for water -0.512°C/m. 101.64°C 100.42°C 99.626°C 100.73°C 101.42°C a. b. C. vapor pressure raising boiling point elevation freezing point depression All of the above are colligative properties 10. Calculate the freezing point of a solution that contains 8.0 g of sucrose (CH₂011) in 100. g of H₂O. K for H₂O= 1.86°C/m. Equation Sheet -0.044°C - 0.22°C - 0.39°C -0.44°C 0.04°C e. 11. The freezing point of an aqueous solution containing 15 g of a nonelectrolyte in 150 ml water is -5.4° What is the molecular weight of the compound? Kr-1.86°C/m for water. M 121 g/mol. 2.78 g/mol 34.4 g/mol 41.2 g/mol. 53.8 g/mol ID: A C. d. e. 12. To increase the solubility of a solid in a liquid solvent, the solvent-solvent interactions shoule and the solute-solute interactions should be strong; weak weak; weak strong; strong weak; strong of a solute in a solvent the solute-solute interactions should be 7. Which of the following is not a colligative property? a. osmotic pressure b. c. 8. Sucrose is a nonvolatile, nonionizing solute in water. Determine the vapor pressure lowering, at 27°C, of a solution of water at 27°C is 26.7 torr. Assume the solution is ideal. 0.585 torr 0.058 torr 0.572 torr 5.62 torr d. b. c. d. a. b. C. d. b. C. d. c. a. b. e. 0.548 torr 9. If 4.27 grams of sucrose, C₁2H₂2011, are dissolved in 15.2 grams of water, what will be the boiling point of the resulting solution? Ks for water -0.512°C/m. 101.64°C 100.42°C 99.626°C 100.73°C 101.42°C a. b. C. vapor pressure raising boiling point elevation freezing point depression All of the above are colligative properties 10. Calculate the freezing point of a solution that contains 8.0 g of sucrose (CH₂011) in 100. g of H₂O. K for H₂O= 1.86°C/m. Equation Sheet -0.044°C - 0.22°C - 0.39°C -0.44°C 0.04°C e. 11. The freezing point of an aqueous solution containing 15 g of a nonelectrolyte in 150 ml water is -5.4° What is the molecular weight of the compound? Kr-1.86°C/m for water. M 121 g/mol. 2.78 g/mol 34.4 g/mol 41.2 g/mol. 53.8 g/mol ID: A C. d. e. 12. To increase the solubility of a solid in a liquid solvent, the solvent-solvent interactions shoule and the solute-solute interactions should be strong; weak weak; weak strong; strong weak; strong of a solute in a solvent the solute-solute interactions should be
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The detailed answer for the above question is provided below Answer 7 All of the above are colligative properties 8 0058 torr 9 10042C 10 022C 11 412 gmol 12 weak strong Explanation 7 Colligative prop... View the full answer
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