77 The hexadecimal dump from part of a computer's memory is as follows: 47FE B087 0086 3253 0000: 0010: 4265 C800 6769 E000 6EFA 0000 7A29 The dump is made up of rows of groups of four hexadecimal characters. Each row contains up to nine 16-bit groups. The first group of a row (terminated in a colon) is an address and defines the first location into which the following groups are to be loaded. For example, the first group in the second row is $0010. The second group is $C800 which is the contents of location $0010. The next group, $E000, is the contents of $0012, and so on. The 22 bytes of data represent the following sequence of items: five consecutive ASCII-encoded characters b. one unsigned 16-bit integer one two's complement 16-bit integer d. one unsigned 16-bit fraction one 6-digit natural BCD integer f. two 32-bit IEEE format floating point numbers a. c. e. Interpret the hexadecimal dump and convert it into the six items above. For example, convert the floating point numbers to decimal form. 77 The hexadecimal dump from part of a computer's memory is as follows: 47FE B087 0086 3253 0000: 0010: 4265 C800 6769 E000 6EFA 0000 7A29 The dump is made up of rows of groups of four hexadecimal characters. Each row contains up to nine 16-bit groups. The first group of a row (terminated in a colon) is an address and defines the first location into which the following groups are to be loaded. For example, the first group in the second row is $0010. The second group is $C800 which is the contents of location $0010. The next group, $E000, is the contents of $0012, and so on. The 22 bytes of data represent the following sequence of items: five consecutive ASCII-encoded characters b. one unsigned 16-bit integer one two's complement 16-bit integer d. one unsigned 16-bit fraction one 6-digit natural BCD integer f. two 32-bit IEEE format floating point numbers a. c. e. Interpret the hexadecimal dump and convert it into the six items above. For example, convert the floating point numbers to decimal form