Question: 8. Find two consecutive odd integers such that their product is 79 more than 8 times their sum. (x+1)(x+3)=79+(2x+4)8 X^2 +3x +x+3=79 + 16x +32

8. Find two consecutive odd integers such that their product is 79 more than 8 times their sum. (x+1)(x+3)=79+(2x+4)8 X^2 +3x +x+3=79 + 16x +32 x^2 -12x-108=0 Area of triangle=20 Base=2x+4 Height=x+3 20=(2x+4)9x+3)/2 2 10=18x^2 +x+6x+12 0=18x^2 +7x +12-10 18x^2 + 7x +2 bxh 4. Area of triangle=16cm^2 Base=x+4 Height=x X(x+4)=16 X^2+4x=16 X^2+4x-16=0 Multiple of -16 Sum of 4

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