Question: 8. Given a normal distribution with = 60 and = 10, complete the following: a) Z = (45-60)/10 = -1.5 . The Z-score indicates that
8. Given a normal distribution with = 60 and = 10, complete the following: a) Z = (45-60)/10 = -1.5 . The Z-score indicates that 45 is usual because usual Z-scores are between -2 and 2. Since -1.5 is between -2 and 2 it's usual. b) To be outside of two standard deviations from the mean, it would have to be lower than 40 or higher than 80. This is because 60-(10*2) is 40 and 60 (10*2) is 80. Since 45 isn't any of those extremes it's inside two standard deviations from the mean. Since it's inside two standard deviations from the mean, it's a usual value. c) The probability that x is less than or equal to 45 is gotten by using a standard normal distribution table. For Z = -1.5, the probability is 6.68%. The probability being 6.68% doesn't mean the value is unusual. This is because the value has to have a probability of 0.025 or 2.5% to be considered unusual
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