Question: 8 sin x (1 point) Let f (x) = 4 sin x + 6 cos x Then f' (x) = The equation of the tangent

8 sin x (1 point) Let f (x) = 4 sin

8 sin x (1 point) Let f (x) = 4 sin x + 6 cos x Then f' (x) = The equation of the tangent line to y = f(x) at a = 7/2 can be written in the form y = mx + b where m = and b = Note: You can earn partial credit on this problem. Preview My Answers Submit Answers

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