8. What is the probability that the person will be under 20 years of age and he/she favors baseball? (A) P (An B) = n (An B) /N = /100 (B) P (A U B) = P (A) + P (B) - P (An B) = 23/100 + 26/100 - 7/100 = 42/100 (C) P (A / B) = n (A and B) / n (B) = /26 (D) P (B/ A) = n (A and B) / n (A) = 1/23 9. What is the probability that the person will be under 20 year of age if he/she favors baseball? (A) P (An B) = n (An B) / N = 8/ 100 (B) P (AU B) = P (A) + P (B) - P (An B) = 23/100 + 26/100 - 7/100 = 42/100 (C) P (A / B) = n (A and B) / n (B) = /26 (D) P (B/ A) = n (A and B) / n (A) = /23 10. Which of the following statements is true? (A) A and B are independent because in favor of baseball is not related to age (B) A and B are not independent because they are disjoint (C) A and B are independent they are not disjoint (D) A and B are not independent because P(B/A) = /23 and P(B) = 2/100 are not equal.Question #8-10 refer to the following table: The table displays the results of a sample of 100 in which the subjects indicated their favorite sport of three listed. The data are organized by favorite sport and age group. AGE FOOTABLE BASEBALL SOCCER Over 40 15 8 Between 20 and 40 20 11 16 Under 20 8 7 8 Choose one person at random from this group and let A = the event that the person is under 20 years of age and B = the person favors Baseball. 7. What is the probability that the person will be under 20 years of age or favors baseball? (A) P (An B) = n (AnB) /N = /100 (B) P (AU B) = P (A) + P (B) - P (An B) = 23/100 + 26/100 - 7/100 = 42/100 (C) P (A/ B) = n (A and B) / n (B) = /26 (D) P (B/A) = n (A and B) / n (A) = 1/23