8. With some modifications, the following algorithm might be used to find an available position in...

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8. With some modifications, the following algorithm might be used to find an available position in the hash table when linear probing is applied as a collision resolution method. A: array of numbers N: number of elements of the array i: index of the array 1 2 3 4 4 i=4 N=5 function TraverseArray (A, N, 1) for 0 <=j<N print (A[(i+j)%N]) What is printed on screen for the following input data? A = [34, 4, 21, 7, 12] end function 8. With some modifications, the following algorithm might be used to find an available position in the hash table when linear probing is applied as a collision resolution method. A: array of numbers N: number of elements of the array i: index of the array 1 2 3 4 4 i=4 N=5 function TraverseArray (A, N, 1) for 0 <=j<N print (A[(i+j)%N]) What is printed on screen for the following input data? A = [34, 4, 21, 7, 12] end function

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The provided algorithm is a bit unclear but it appears to be attempting to traverse an array w... View the full answer