80, 1 and 30 are wrong

With these three graphs in hand, we can now determine the relative amount of R and S in a solution which contains a random amount of each. For the following 2 spectrum, calculate the percentage of the R and S enantiomers. Please save these numbers for later To determine the \%, first determine which enantiomer is more abundant by whether the rotation is positive or negative. From here, take the percentage of the rotation relative to the pure compound. Take half of this number and add 50% to this to get the relative percentage. Example 1: Pure R rotation (after minusing the blank): 50 Pure S rotation (after minusing the blank): 50 Unknown rotation (after minusing the blank): 25 Because this is positive it will be more R than S. 25/50=50%/2+50%=75%R, leaving 25%S Second unknown rotation (after minusing the blank): 10 Because this is negative it will be more S than R. 10/50=20%/2+50=60%S, leaving 40%R Question \#15: Percentage of S enantiomer (UNKNOWN 2): With these three graphs in hand, we can now determine the relative amount of R and S in a solution which contains a random amount of each. For the following 2 spectrum, calculate the percentage of the R and S enantiomers. Please save these numbers for later To determine the \%, first determine which enantiomer is more abundant by whether the rotation is positive or negative. From here, take the percentage of the rotation relative to the pure compound. Take half of this number and add 50% to this to get the relative percentage. Example 1: Pure R rotation (after minusing the blank): 50 Pure S rotation (after minusing the blank): 50 Unknown rotation (after minusing the blank): 25 Because this is positive it will be more R than S. 25/50=50%/2+50%=75%R, leaving 25%S Second unknown rotation (after minusing the blank): 10 Because this is negative it will be more S than R. 10/50=20%/2+50=60%S, leaving 40%R Question \#15: Percentage of S enantiomer (UNKNOWN 2)