8:19 . LTE 86 08PathLoss-Fitting Done From the measurement data, find the empirical exponent that best fit the data. LOB = 20 log (f )+ 10nlog (d)- 147.56 dB Part I: Find a and n to fit the curve a + n x, where x=10 log(d). Solving the above can be done through curve fitting tool in MatLab. It can also be done through equating derivatives w.r.t a and n to zero and solve the resulting system of 2 linear equations. Part II: Second, find n to fit the curve a + n x, Given a=20log(f) - 147.56, f=900MHz. Same as the previous equation but with a fixed. Hence, we cannot use the curve fitting tool. Instead we should differentiate w.r.tn, i.e., solving 1 linear equation. Repeat the above for horizontal and vertical cases. Plot the original and fitted data on the same graph. distance m horizontal average 0.5 77 76 77 78 79 80 81 84 79 1 85 84 86 85 86 86 87 88 85.875 1.5 85 87 88 89 85 88 89 90 87 .625 2 86 89 90 87 86 88 90 91 88.375 2.5 91 89 88 89 88 87 89 91 89 3 92 92 90 88 84 89 91 92 89.75 3.5 92 93 89 89 88 87 92 93 90.375 4 91 92 91 90 85 92 93 94 91 4.5 93 91 90 95 95 91 89 94 92.25 5 95 90 89 96 96 92 91 95 93 distance (m) vertical laverage