Question: 8.2- a) We know all three algorithms are O(na) in terms of the number of comparisons. But to n(n-1) be more specific, selection sort on
8.2- a) We know all three algorithms are O(na) in terms of the number of comparisons. But to n(n-1) be more specific, selection sort on all cases uses comparisons, while insertion sort in worst n(n-1) n(n+1) comparisons, but on average uses only Using this information, if forced to select between these two algorithms, which would you use, and why? 2 cases uses
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