$9$:$39$PM Sun $22$ Sep

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LO$1-$ Stress and Strain

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Done

$-1-53.$ The average shear stress in each of the $6-mm$ diameter bolts and along each of the four shaded shear planes is not allowed to exceed $80$ MPa and $500$ kPa $,$ respectively. Determine the maximum axial force $P$ that can be applied to the joint.

$=\frac{F}{A_P}$

$80Pa=\frac{{}^2}{(3{)}^2}$

$F=2261a$

$=s65\mathrm{.}48N$