$9$:$541$

$5$G

$72$

knewton.com

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Question

Evaluate the integral.

${\displaystyle \underset{0}{\overset{\frac{}{4}}{}}}(ta{n}^5(x))(-se{c}^3(x))dx$

Give an exact answer.

Provide your answer below:

${\displaystyle \underset{0}{\overset{\frac{}{4}}{}}}(ta{n}^5(x))(-se{c}^3(x))dx=$

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