$9.(7$ points$)$ You obtained the following information from a workstation:

C:$\backslash >$ipconfig

IP Address. $........$ : $10\mathrm{.}0\mathrm{.}0\mathrm{.}98$

Subnet Mask $.......$ : $255\mathrm{.}255\mathrm{.}0\mathrm{.}0$

Default Gateway $....$ : $10\mathrm{.}0\mathrm{.}250\mathrm{.}254$

You then check the arp table with the following entry:

C:$\backslash >$arp $-$a

Interface: $10\mathrm{.}0\mathrm{.}0\mathrm{.}98$ on Interface $2$

Internet Address Physical Address

$10\mathrm{.}0\mathrm{.}250\mathrm{.}25400-$e$0-$b$0-$ac$-$ac$-$a$8$

$10\mathrm{.}0\mathrm{.}255\mathrm{.}255$ ff:ff:ff:ff:ff:ff

Next, you execute the following command:

C:$\backslash >$ping $10\mathrm{.}0\mathrm{.}255\mathrm{.}255$

And received the following reply:

Pinging $10\mathrm{.}0\mathrm{.}255\mathrm{.}255$ with $32$ bytes of data:

Reply from $10\mathrm{.}0\mathrm{.}255\mathrm{.}255$: bytes$=32$ time$<10$ms TTL$=255$

Reply from $10\mathrm{.}0\mathrm{.}255\mathrm{.}255$: bytes$=32$ time$<10$ms TTL$=255$

Reply from $10\mathrm{.}0\mathrm{.}255\mathrm{.}255$: bytes$=32$ time$<10$ms TTL$=255$

Finally, you obtained the following:

C:$\backslash >$ arp $-$a

Interface: $10\mathrm{.}0\mathrm{.}0\mathrm{.}98$ on Interface $2$

Internet Address Physical Address

$10\mathrm{.}0\mathrm{.}116\mathrm{.}2100-00-$f$4-$a$9-9$d$-$d$4$

$10\mathrm{.}0\mathrm{.}224\mathrm{.}3400-00-1$d$-0$f$-4$b$-71$

$10\mathrm{.}0\mathrm{.}108\mathrm{.}200-00-$f$4-$a$9-98-21$

$10\mathrm{.}0\mathrm{.}17\mathrm{.}12900-00-$f$4-$b$1-$b$6-57$

$10\mathrm{.}0\mathrm{.}7\mathrm{.}14100-10-5$a$-05-$ef$-$f$9$

$10\mathrm{.}0\mathrm{.}0\mathrm{.}15300-60-$b$0-79-$c$3-80$

$10\mathrm{.}0\mathrm{.}255\mathrm{.}255$ ff:ff:ff:ff:ff:ff

$10\mathrm{.}0\mathrm{.}1\mathrm{.}25000-00-0$c$-4$e$-32-90$

$10\mathrm{.}0\mathrm{.}1\mathrm{.}25100-00-0$c$-4$e$-32-90$

$10\mathrm{.}0\mathrm{.}250\mathrm{.}254$

$00-$e$0-$b$0-$ac$-$ac$-$a$8$

a How can you account for the new entries in the arp table?