$9.$ From point $1$ a BM of elevation $289\mathrm{.}12$ is sighted with a zenith circle of $88$d$4545,$ slope distance of $175\mathrm{.}15$ and an HT of $5\mathrm{.}45.$ What is the elevation of a horizontal line of sight of the instrument at point $1?$

Help$-$ elev BM $+$ HT $$ slop dist $*$ cos $($zenith angle$)$

Note HI not involved as you are computing the elev of the instrument$$s center